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63
Solution.
We use Exercise 2.69:
Q
has exactly one element of order 2,
while
D
8
has 5 elements of order 2.
2.88
If
G
is a
f
nite group generated by two elements of order 2, prove that
G
∼
=
D
2
n
for some
n
≥
2.
Solution.
Absent.
2.89
(i)
Prove that
A
3
is the only subgroup of
S
3
of order 3.
Solution.
Absent.
(ii)
Prove that
A
4
is the only subgroup of
S
4
of order 12. (In Exer
cise 2.135, this will be generalized from
S
4
and
A
4
to
S
n
and
A
n
for all
n
≥
3.)
Solution.
If
H
is a subgroup of order 12, then
H
is normal (it
has index 2), and so it contains all the conjugates of each of its
elements. It must contain 1. We count the number of conjugates of
the various types of permutations (each count uses Exercise 2.24:
(
12
)
has 6 conjugates;
(
123
)
has 8 conjugates;
(
1234
)
has 6
conjugates;
(
)(
34
)
has 3 conjugates. The only way to get 12
elements is 1
+
3
+
8; but this is
A
4
.
2.90
(i)
Let
A
be the set of all 2
×
2 matrices of the form
A
=
£
ab
01
±
, where
a
±=
0. Prove that
A
is a subgroup of GL
(
2
,
R
)
.
Solution.
It is a routine calculation to show that if
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This note was uploaded on 12/21/2011 for the course MAS 4301 taught by Professor Keithcornell during the Fall '11 term at UNF.
 Fall '11
 KeithCornell

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