148_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

148_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
142 CHAPTER 2 Axially Loaded Members upward displ. due to shortening of steel wires & elongation of alum. wire under redundant R A enforce compatibility & then solve for R A 1 2 so and now use statics to find R S and compute stresses & apply allowable stress values solve for allowable load P lower value of P controls P Aa 1713 N P Sa 1504 N P allow is controlled by steel wires (b) P allow if load P at x a/2 again, cut aluminum wire at top, then compute elongations of left & right steel wires where 1 displ. at x a Use 2 from (a) above so equating 1 & 2 , solve for R A same as in (a) stress in left steel wire exceeds that in right steel wire R SL 3P 4 + W 2 (P + W) E A A A E A A A + 2E S A S 2 R SL 3P 4 + W 2 R A 2 R A ( P + W) E A A A E A A A + 2E S A S d 2 R
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: b d 1 ³ d 1L + d 1R 2 d 1R ³ a P 4 + W 2 ba L E S A S b d 1L ³ a 3P 4 + W 2 ba L E S A S b ; P Sa ³ s Sa a E A A A + 2E S A S E S b ´ W P Aa ³ s Aa a E A A A + 2E S A S E A b ´ W s Sa ³ ( P + W) E S E A A A + 2E S A S s Aa ³ ( P + W) E A E A A A + 2E S A S s Sa ³ R S A S R S ³ (P + W) E S A S E A A A + 2E S A S R S ³ P + W ´ (P + W) E A A A E A A A + 2E S A S 2 R S ³ P + W ´ R A 2 s Aa ³ R A A A R A ³ ( P + W) E A A A E A A A + 2E S A S R A ³ P + W 2 a L E S A S b L 2E S A S + L E A A A d 2 ³ R A a L 2E S A S + L E A A A b Sec_2.4.qxd 9/25/08 11:38 AM Page 142...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern