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Unformatted text preview: Sec_2.5.qxd 9/25/08 3:00 PM Page 157 SECTION 2.5 Thermal Effects Solution 2.5-8 Brass sleeve fitted over a Steel bolt
sS ¢T ES(aS aB) a1 + ES AS
EB AB ; SUBSTITUTE NUMERICAL VALUES:
25 MPa S d2
ES Subscript S means “sleeve”. 36 mm
100 GPa Subscript B means “bolt”. 21 S Use the results of Example 2-8.
S EQUATION (2-20A):
aB)( ¢ T)ES EB AB
ES AS + EB AB
SOLVE FOR T:
¢T sS(ES AS + EB AB)
aB)ES EB AB EB 10 /°C AS p2
4 (aS 26 mm d2)
1 B 10 p
4 ES AS
(625 mm2) 1 +
EB AB (100 GPa)(11 * 10
34°C 6 /°C) ; (Increase in temperature) or Problem 2.5-9 Rectangular bars of copper and aluminum are held by
pins at their ends, as shown in the figure. Thin spacers provide a separation
between the bars. The copper bars have cross-sectional dimensions
0.5 in. 2.0 in., and the aluminum bar has dimensions 1.0 in. 2.0 in.
Determine the shear stress in the 7/16 in. diameter pins if the temperature is raised by 100°F. (For copper, Ec 18,000 ksi and c 9.5
10 6/°F; for aluminum, Ea 10,000 ksi and a 13 10 6/°F.)
Suggestion: Use the results of Example 2-8. Solution 2.5-9 Rectangular bars held by pins Diameter of pin: dP
Area of pin: AP 7
4P 0.4375 in. 0.15033 in.2 Area of two copper bars: Ac
Area of aluminum bar: Aa
T 100°F 25 mm 10 6/°C 25 MPa (1.496) ¢T
T dB 200 GPa 6 AB compressive force in sleeve d1 2.0 in.2
2.0 in.2 1.496 157 ...
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This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.
- Fall '11