168_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

168_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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Unformatted text preview: Sec_2.5.qxd 9/25/08 162 3:00 PM Page 162 CHAPTER 2 Axially Loaded Members Solution 2.5-13 numerical data L 25 in. d k 1.2 compressive stress in bar RA s 957 psi A 0.008 in. 2 in. 6 (10 ) lb/in. E 16 (106) psi (b) force in spring Fk RC statics RA RC 0 RA RC RC 3006 lb ; 9.6 (10 6)/°F T 50°F p2 d A 3.14159 in2 A 4 (a) one-degree stat.-indet. if gap closes TL 0.012 in. (c) find compressive stress in bar if k goes to infinity from expression for RA above, 1/k goes to zero, so exceeds gap select RA as redundant & do superposition analysis A1 compatibility RA RAa d A2 A1 d ¢ L 1 + EA k L 1 +b EA k A2 RA A2 RA d ¢ L EA 2560 psi A1 RA A s 8042 lb ; 3006 lb 2L — 3 Problem 2.5-14 A bar AB having length L and axial rigidity EA is fixed at end A (see figure). At the other end a small gap of dimension s exists between the end of the bar and a rigid surface. A load P acts on the bar at point C, which is two-thirds of the length from the fixed end. If the support reactions produced by the load P are to be equal in magnitude, what should be the size s of the gap? Solution 2.5-14 RA A s L — 3 C B P Bar with a gap (load P ) FORCE-DISPLACEMENT RELATIONS d1 L size of gap EA length of bar S P A 2L B 3 EA axial rigidity Reactions must be equal; find S. d2 RBL EA ...
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This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

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