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192_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

# 192_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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186 CHAPTER 2 Axially Loaded Members using x cos( ) 2 34.2° now with , can find shear stress on plane pq pq x sin( )cos( ) pq 1154 psi pq x cos( ) 2 pq 1700 psi stresses at /2 (y face) y 784 psi (b) S TRESS ELEMENT FOR PLANE PQ (c) M AX . LOAD AT QUARTER POINT a 3400 psi a 1650 psi 2 a 3300 less than a so shear controls stat-indet analysis for P at L/4 gives, for reactions: (tension for 0 to L/4 & compression for rest of bar) R L2 3 4 P R R2 P 4 784 psi 1154 psi 1700 psi Part (b) θ = 34.2 ° s y s x cos a u + p 2 b 2 ; u acos a A s pq s x b cos 1 u 2 2 s pq s x from (a) (for temperature increase T): R R1 EA T R L1 EA T Stresses in bar (0 to L/4) set max a & solve for P max1 P

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