208_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

# 208_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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Unformatted text preview: Sec_2.7.qxd 9/25/08 202 11:42 AM Page 202 CHAPTER 2 Axially Loaded Members At the proportional limit: At the proportional limit: u modulus of resistance uR s2 PL uR uW s2 PL 2gE (Eq. 2) (Eq. 1) 2E RESULTS STRAIN ENERGY PER UNIT WEIGHT 2 PL 2EA U Weight W gAL weight density 22 94 171 150 Mild steel Tool steel Aluminum Rubber (soft) uw (in.) 76 330 1740 3700 s2 2gE U W uW uR (psi) Problem 2.7-6 The truss ABC shown in the figure is subjected to a horizontal load P at joint B. The two bars are identical with cross-sectional area A and modulus of elasticity E. (a) Determine the strain energy U of the truss if the angle 60°. (b) Determine the horizontal displacement B of joint B by equating the strain energy of the truss to the work done by the load. Solution 2.7-6 Truss subjected to a load P 13/2 cos 1/2 LAB LBC L FREE-BODY DIAGRAM OF JOINT B Fvert 0 FAB sin FAB ↓ FBC sin 0 FBC (Eq. 1) 0:← Fhoriz FAB cos FAB ↓ sin b 60° FBC FBC cos P P 2 cos b P 2(1/2) 0 P (Eq. 2) ...
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## This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

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