224_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

# 224_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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Unformatted text preview: Sec_2.8-2.12.qxd 218 9/25/08 11:44 AM Page 218 CHAPTER 2 Axially Loaded Members Problem 2.8-9 Solve the preceding problem if the slider has weight W 100 lb, h 45 in., A and the allowable stress is 70 ksi. 0.080 in.2, E 21 106 psi, Cable Slider L h Restrainer Solution 2.8-9 Slider on a cable STATIC STRESS sst 100 lb W A 0.080 in.2 1250 psi MINIMUM LENGTH Lmin sst c 1 + a 1 + 59): smax Eq. (2 2hE 1/2 bd Lsst or smax sst 1 a1 + 2hE 1/2 b Lsst Square both sides and solve for L: L Lmin 2Ehsst smax(smax 2sst) ; SUBSTITUTE NUMERICAL VALUES: W A 0.080 in.2 h 45 in Lmin 100 lb E allow 21 max Find minimum length Lmin 106 psi 70 ksi 2(21 * 106 psi) (45 in.) (1250 psi) (70,000 psi) [70,000 psi 2(1250 psi)] 500 in. ; ...
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## This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

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