240_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

240_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Sec_2.8-2.12.qxd 234 9/25/08 11:44 AM Page 234 CHAPTER 2 Axially Loaded Members Solution 2.11-4 L 2.0 m A Bar in tension 249 mm2 STRESS-STRAIN DIAGRAM (See the problem statement for the diagram) LOAD-DISPLACEMENT DIAGRAM P (kN) P/A (MPa) (from diagram) L (mm) 10 20 30 40 45 40 80 120 161 181 0.0009 0.0018 0.0031 0.0060 0.0081 NOTE: The load-displacement curve has the same shape as the stress-strain curve. 1.8 3.6 6.2 12.0 16.2 Problem 2.11-5 An aluminum bar subjected to tensile forces P has length L 150 in. and cross-sectional area A 2.0 in.2 The stress-strain behavior of the aluminum may be represented approximately by the bilinear stress-strain diagram shown in the figure. Calculate the elongation of the bar for each of the following axial loads: P 8 k, 16 k, 24 k, 32 k, and 40 k. From these results, plot a diagram of load P versus elongation (load-displacement diagram). s 12,000 psi E2 = 2.4 106 psi E1 = 10 106 psi 0 e ...
View Full Document

This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

Ask a homework question - tutors are online