240_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

# 240_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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Unformatted text preview: Sec_2.8-2.12.qxd 234 9/25/08 11:44 AM Page 234 CHAPTER 2 Axially Loaded Members Solution 2.11-4 L 2.0 m A Bar in tension 249 mm2 STRESS-STRAIN DIAGRAM (See the problem statement for the diagram) LOAD-DISPLACEMENT DIAGRAM P (kN) P/A (MPa) (from diagram) L (mm) 10 20 30 40 45 40 80 120 161 181 0.0009 0.0018 0.0031 0.0060 0.0081 NOTE: The load-displacement curve has the same shape as the stress-strain curve. 1.8 3.6 6.2 12.0 16.2 Problem 2.11-5 An aluminum bar subjected to tensile forces P has length L 150 in. and cross-sectional area A 2.0 in.2 The stress-strain behavior of the aluminum may be represented approximately by the bilinear stress-strain diagram shown in the figure. Calculate the elongation of the bar for each of the following axial loads: P 8 k, 16 k, 24 k, 32 k, and 40 k. From these results, plot a diagram of load P versus elongation (load-displacement diagram). s 12,000 psi E2 = 2.4 106 psi E1 = 10 106 psi 0 e ...
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## This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

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