268_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

268_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Sec_3.3.qxd 262 9/27/08 1:27 PM Page 262 CHAPTER 3 Torsion Solution 3.3-14 Vertical pole TORSION FORMULA Tr IP tmax T pd 4 32 IP P(2c + d) P(2c + d)d 16P (2c + d) 4 tmax ( Td 2IP pd 3 pd /16 max) d 3 (16P) d 32Pc 0 SUBSTITUTE NUMERICAL VALUES: P 5.0 kN UNITS: Newtons, Meters c 125 mm ( )(30 allow 30 MPa or Find dmin d3 106)d3 848.826 (16)(5000)d 10 6d Solve numerically: 212.207 d dmin Problem 3.3-15 A solid brass bar of diameter d 1.25 in. is subjected to torques T1, as shown in part (a) of the figure. The allowable shear stress in the brass is 12 ksi. (a) What is the maximum permissible value of the torques T1? (b) If a hole of diameter 0.625 in. is drilled longitudinally through the bar, as shown in part (b) of the figure, what is the maximum permissible value of the torques T2? (c) What is the percent decrease in torque and the percent decrease in weight due to the hole? T1 32(5000)(0.125) 10 6 0 0 0.06438 m 64.4 mm d ; T1 (a) d T2 T2 (b) ...
View Full Document

Ask a homework question - tutors are online