SECTION 3.7Transmission of Power297Solution 3.7-5Hollow shaftd±outside diameterd0±inside diameter±0.75dH±400 hpn±400 rpm²allow±6000 psiTORQUEH±2pnT33,000 IP±p32[d4³(0.75 d)4]±0.067112 d4 H±hpn±rpmT±lb-ft±5252.1 lb-ft±63,025 lb-in.MINIMUM OUTSIDE DIAMETERd3±78.259 in.3dmin±4.28 in.;0.067112 d4±(63,025 lb-in.)(d)2(6000 psi) tmax±Td2IPIP±Td2tmax±Td2tallowT±33,000 H2pn±(33,000)(400 hp)2p(400 rpm) Problem 3.7-6A tubular shaft being designed for use on a construction site must transmit 120 kW at 1.75 Hz. The insidediameter of the shaft is to be one-half of the outside diameter.If the allowable shear stress in the shaft is 45 MPa, what is the minimum required outside diameter d?Solution 3.7-6Tubular shaftd±outside diameterd0±inside diameter±0.5dP±120 kW±120,000 Wf±1.75 Hzallow±45 MPaTORQUEP±2´fT P±watts
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This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.