338_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

338_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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Unformatted text preview: Sec_3.9-3.11.qxd 332 9/27/08 1:14 PM Page 332 CHAPTER 3 Torsion Solution 3.10-7 Elliptical tube 1ab] FROM APPENDIX D, CASE 16: Am pab 26.0 in.2] p(3.0 in.)(2.0 in.) Lm L p[1.5(a + b) p[1.5(5.0 in.) J 18.850 in.2 15.867 in. 4(0.2 in.)(18.850 in.2)2 15.867 in. 4tA2 m Lm 17.92 in.4 T 18 k-in. G 12 SHEAR STRESS 106 psi t t 0.2 in t constant a 3.0 in. b 2.0 in. 18 k-in. T 2tAm 2(0.2 in.)(18.850 in.2) ; 2390 psi ANGLE OF TWIST PER UNIT LENGTH (RATE OF TWIST) u f L u 83.73 * 10 T GJ 18 k-in. (12 * 106 psi)(17.92 in.)4 6 rad/in. Problem 3.10-8 A torque T is applied to a thin-walled tube having a cross section in the shape of a regular hexagon with constant wall thickness t and side length b (see figure). Obtain formulas for the shear stress and the rate of twist . ; 0.0048°/in. t b Solution 3.10-8 Regular hexagon b Length of side t Thickness Lm 6b FROM APPENDIX D, CASE 25: 60° n 3 13b2 2 2 Am 6 b nb cot 4 2 6b2 cot 30° 4 ...
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This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

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