388_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

388_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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382 CHAPTER 4 Shear Forces and Bending Moments Problem 4.5-37 The inclined beam below represents the loads applied to a ladder: the weight ( W ) of the house painter and the self weight ( w ) of the ladder itself. Find support reactions at A and B , then plot axial force ( N ), shear ( V ) and moment ( M ) diagrams. Label all critical N , V & M values and also the distance to points where any critical ordinates are zero. Plot N , V & M diagrams normal to the inclined ladder. 8 ft 6 ft
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Unformatted text preview: 18 ft w = 2.5 lb/ft B x A x A y B A θ θ θ θ θ θ W = 150 lb Solution 4.5-37 M N V –16.79 lb –30.98 lb –172.4 lb –214.8 lb 270 lb·ft 22.5 lb 7.5 lb –42.5 lb –47.5 lb cos θ = 0.833 lb/ft A x cos θ + A y sin θ = 214.8 lb B x cos θ = –16.79 lb B x sin θ = 47.5 lb A y cos θ – A x sin θ = 22.5 lb B A W cos θ = 50 lb sin = 2.357 lb/ft W = 141.4 lb 04Ch04.qxd 9/25/08 12:43 PM Page 382...
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This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

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