431_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

# A b d c b l a q a d b c l b solution 56 18 numerical

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Unformatted text preview: b L (a) q A D B C L (b) Solution 5.6-18 NUMERICAL DATA L b 915 mm sallow 2 12) Substitute x into the equation for either M1 or |M2|: 305 mm t 22 mm Mmax Mmax 7.5 MPa MOMENT DIAGRAM qL2 (3 8 sallow S sallow a 2 12) Eq. (1) bt 2 b 6 Eq. (2) Equate Mmax from Eqs. (1) and (2) and solve for q: qmax 4bt2sallow 3L2(3 Substitute numerical values: For maximum load-carrying capacity, place the supports so that M1 |M2|. Let x M1 ‹ length of overhang qL (L 8 qL (L 8 4x) 4x) Solve for x: x |M2| L ( 12 2 qx2 2 1) qx2 2 qmax 10.28 kN/m ;...
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## This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

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