462_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

462_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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Unformatted text preview: 05Ch05.qxd 9/25/08 456 2:29 PM Page 456 CHAPTER 5 Stresses in Beams (Basic Topics) Solution 5.9-4 Wind load on a sign b b (b) REQUIRED DIAMETER BASED UPON SHEAR STRESS width of sign 3.0 m p t sallow 50 MPa tallow 16 MPa d diameter t d 10 r1 W wind force on one pole b ph2 a b 2 W p4 (d 64 2 s Mc I d2 d d1 d I p4 cd 64 a I 2t d 2 s Mc I d3 (d d4) 1 A t d2 M(d/2) 17.253 M 369pd 4/40,000 d3 (17.253)(54.675 kN # m) 17.253Mmax sallow 50 MPa 266 m d 10 2d 5 d1 2) a 4d 2 bd 5 100 4V 61 a ba b 3 41 9pd2 7.0160 Vmax tallow 9pd2 100 7.0160 V d2 (7.0160)(8.1 kN) 14 MPa 0.004059 m2 meters) d 0.266 m p (d 2 42 p2 cd 4 369pd 4 (m 4) 40,000 d 2 ; d 2 d2 2d 2 a b +a b 2 5 4 d 5 0.018866 m3 d t 54.675 kN # m 4d 4 bd 5 pd 4 369 a b 64 625 d 2 r2 r2 2 + r1 2 d 2d 2d 2 d2 a b + a ba b + a b 2 5 5 5 8.1 kN h2 W a h1 + b 2 4V r2 + r1 r2 + r1 2 a b 3A r2 2 + r1 2 r2 2 + r1r2 + r1 2 (a) REQUIRED DIAMETER BASED UPON BENDING STRESS c 8.1 kN 2 3.6 kPa Mmax W Vmax 0.06371 m 63.7 mm Bending stress governs ; 61 41 ...
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This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

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