{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

468_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

# 468_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

This preview shows page 1. Sign up to view the full content.

462 CHAPTER 5 Stresses in Beams (Basic Topics) Solution 5.10-9 Beam with an overhand Sum moments about A & Solve for R B Sum forces in vertical direction M B 2.16 * 10 4 lb-ft M B P (4 ft) q (4 ft) 2 2 V max 1.1 * 10 4 lb at B V max R B ( P + q 4 ft) R A 6.4 * 10 3 lb R A q (16 ft) + 2 P R B R B 1.88 * 10 4 lb R B q a 4 3 L b 2 1 2 + P (8 ft + 16 ft) 12 ft q 1200 lb ft P 3000 lb s allow 18 ksi t allow 11 ksi L 12 ft Find moment at D (at Load P between A and B ) Required section modulus: Lightest beam is (from Table E-2(a)) Check max. shear stress ; Select S 8 * 23 beam t max 3674 6 11,000 psi so ok for shear t max V max 8 It 1 bh 2 bh 1 2 + th 1 2 2 h 1 h 2 t f h 1 7.15 in. h 8 in. t f 0.425 in. t 0.441 in. b 4.17 in. S 16.2 in. 3 I 64.7 in. 4 S 8 * 23 S M max s allow S 14.4 in. 3 M max | M B | M max 2.16 * 10 4 lb-ft M D 1.28 * 10 4 lb-ft M D R A 8 ft q (8 ft) 2 2 (b) M AXIMUM LOAD BASED UPON SHEAR STRESS t max V max 8 It 1 bh 2 bh 1 2 + th 1 2 2 V max R A 3 8 qL t allow 50 MPa Bending stress governs: q max 184.7 kN/m ; ; q max 247 kN/m q max 64 t allow It w 3 L 1 bh 2 bh 1 2 t w h 1 2 2 3 qL 64 It 1 bh 2 bh 1 2 + th 1 2 2 Problem 5.10-9 A simple beam with an overhang supports a uniform
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Ask a homework question - tutors are online