487_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

# 487_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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SECTION 5.12 Beams with Axial Loads 481 Solution 5.12-8 (a) D ISREGARD WEIGHT OF BAR M AX . TENSILE STRESS AT TOP OF BEAM AT SUPPORT s allow ± 4 T p d 2 + 32 M p d 3 s max ± T A + M I d 2 ± T p 4 d 2 + M p 64 d 4 d 2 A ± p 4 d 2 c ± d 2 I ± p 64 d 4 s allow ± 110 MPa L ± 2.5 m g steel ± 77 kN m 3 T ± 24 kN M ± 3.5 kN # m SOLVE NUMERICALLY FOR d ( SUBSTITUTE ) (b) I NCLUDE WEIGHT OF BAR A T TOP OF BEAM AT SUPPORT S UBSTITUTE M MAX FROM ABOVE , SOLVE FOR d NUMERICALLY ; d ± 76.5 mm s t ± s allow ± T A + M max I d 2 M max ± M + A g steel L 2 2 d ± 70 mm ; s allow T ENSILE STRESS ( EQUAL TO ZERO ) + W I a h 2 sin a ba d 2 2 b ± 0 s t ±² N A + Mc I ±² W cos a A M AXIMUM ANGLE ; a ± arctan d 2 2 + d 1 2 4 hd 2 a cos a A ± hd 2 sin a 4 I tan a ± 4 I hd 2 A ± d 2 2 + d 1 2 4 hd 2 Problem 5.12-8 A steel bar of solid circular cross section and length
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Unformatted text preview: is subjected to an axial tensile force and a bending moment (see figure). (a) Based upon an allowable stress in tension of , determine the required diameter of the bar; disregard the weight of the bar itself. (b) Repeat (a) including the weight of the bar. d 110 MPa M ± 3.5 kN m T ± 24 kN L ± 2.5 m M d y z – z-direction T L x 05Ch05.qxd 9/25/08 2:29 PM Page 481...
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## This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

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