530_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

530_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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524 CHAPTER 6 Stresses in Beams (Advanced Topics) Problem 6.4-7 Solve the preceding problem for a cantilever beam with data as follows: b ± 4 in., h ± 9 in., L ± 10.0 ft, P ± 325 lb, and a ± 45°. Solution 6.4-7 L ± 10.0 ft P ± 325 lb b ± 4 in. h ± 9 in. a ± 45° B ENDING MOMENTS M y ± P cos( a ) LM y ± 27577 lb in. M z ±² P sin( a ) z 27577 lb in. M OMENT OF INERTIA I z ± bh 3 12 I z ± 243.000 in. 4 I y ± hb 3 12 I y ± 48.000 in. 4 # # N EUTRAL AXIS nn b 79.3° ; b ± a tan a I z I y tan( a + 90°) b M AXIMUM TENSILE STRESS ( AT POINT A) s max ± 8.87 MPa ; s max ± M y a b 2 b I y ² M z a h 2 b I z N EUTRAL AXIS nn M AXIMUM TENSILE STRESS ( AT POINT A) s max ± 1660 psi ; s max ± M y a b 2 b I y ² M z a h 2 b I z b 78.8 deg ; b ± a tan a I z I y tan( a + 90°) b Problem 6.4-8 A steel beam of I-section (see figure) is simply supported at the ends. Two equal and oppositely directed bending moments
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This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

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