531_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

531_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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Unformatted text preview: 06Ch06.qxd 9/24/08 5:54 AM Page 525 525 SECTION 6.4 Beams with Inclined Loads Solution 6.4-8 4.0 kN # m Mo S 200 Iz 27.4 23.9 a Iy NEUTRAL AXIS nn 24° 1.54 106 mm4 d 106 mm4 203 mm b 102 mm M0 sin(a) Mz My a 1627 N # m My M0 cos(a) Mz b ; 81.8° MAXIMUM TENSILE STRESS (AT POINT A) BENDING MOMENTS My Iz a tan a tan( a) b Iy b 3654 N # m smax b b 2 Mz a Iy smax d b 2 Iz ; 69.4 MPa Problem 6.4-9 A cantilever beam of wide-flange cross section and length y L supports an inclined load P at its free end (see figure). Determine the orientation of the neutral axis and calculate the maximum tensile stress smax due to the load P. Data for the beam are as follows: W 10 45 section, L 8.0 ft, P 1.5 k, and a 55°. (Note: See Table E-1a of Appendix E for the dimensions and properties of the beam.) P a z C Probs. 6.4-9 and 6.4-10 Solution 6.4-9 Cantilever beam with inclined load BENDING MOMENTS My (P cos a)L 82,595 lb-in. Mz (P sin a)L 117,960 lb-in. NEUTRAL AXIS nn (EQ. 6-23) u a 90° Iz tan b Iy b P 1.5 k 8.0 ft 96 in. a 55° (see Fig. 6-15) 248 tan 35° 53.4 tan u 3.2519 ; 72.91° 1500 lb L 35° W 10 Iy d MAXIMUM TENSILE STRESS (POINT A) (EQ. 6-18) zA yA 45 53.4 in.4 10.10 in. b/2 Iz b 248 in.4 8.02 in. d/2 smax sA 4.01 in. 5.05 in. My zA Mz yA Iy Iz 8600 psi ; ...
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This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

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