603_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

# 603_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 07Ch07.qxd 9/27/08 1:19 PM Page 597 597 SECTION 7.4 Mohr’s Circle Solution 7.4-4 sx sy 48 MPa (a) ELEMENT AT 2u u Point C: sx sc (b) MAXIMUM SHEAR STRESSES Point S1: us1 |sx| + |sy| R 2 sc sx + R Point D: sx1 0 MPa ; 25° 50.0 deg R txy 19 MPa us1 33.5 MPa tmax 14.5 MPa tx1y1 R sin(2u) tx1y1 tmax 90° 2 sc ; 45.0° tmax R saver saver ; 33.5 MPa 14.5 MPa ; sc + R cos(2u) sy1 7.0 MPa Problem 7.4-5 An element in biaxial stress is subjected to stresses sx and sy ; 33.5 MPa us2 ; 25.7 MPa Point D œ : sy1 tmax R ; 36.0 MPa ; 45.0° Point S2: us2 R cos(2u) sx1 90° 2 6250 psi 1750 psi, as shown in the figure. Using Mohr’s circle, determine: y (a) The stresses acting on an element oriented at a counterclockwise angle u 55° from the x axis. (b) The maximum shear stresses and associated normal stresses. Show all results on sketches of properly oriented elements. 1750 psi 6250 psi O x Solution 7.4-5 sx sy 6250 psi (a) ELEMENT AT 2u u Point D: sx1 sx1 0 psi |sx| + |sy| 2 sx R R sc tx1y1 sc 45° R Point S2: us2 ; 3464 psi Point D œ : sy1 us1 tmax 2250 psi R cos(2u) tmax 90° 2 ; ; 4000 psi us2 ; 45° tmax ; sy1 4250 psi R tmax 4000 psi ; saver R sin (2u) tx1y1 90° 2 4000 psi sc + R cos(2u) 250 psi (b) MAXIMUM SHEAR STRESSES Point S1: us1 60° 120° R Point C: sc txy 1750 psi sc saver 2250 psi ; ...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online