609_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

609_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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Unformatted text preview: 07Ch07.qxd 9/27/08 1:19 PM Page 603 603 SECTION 7.4 Mohr’s Circle Solution 7.4-15 5700 psi sy sx u 950 psi txy 2100 psi Point D: sx1 65° saver R 2(sx sx1 sx + sy a atan a b saver + R cos ( b ) saver 2 2 saver) + txy |txy| 180° |sx saver| 2 b 2u + a tx1y1 2375 psi R a b R sin ( b ) Point D sy1 œ: saver sy1 3933 psi ; 1846 psi tx1y1 ; 3897 psi R cos ( b ) ; 2904 psi 32.28° 82.28° Problems 7.4-16 sx y 29.5 MPa, sy 29.5 MPa, txy 27 MPa Using Mohr’s circle, determine (a) the principal stresses and (b) the maximum shear stresses and associated normal stresses. Show all results on sketches of properly oriented elements. sy txy sx O x Probs. 7.4-16 through 7.4-23 Solution 7.4-16 sx 29.5 MPa sy saver R a 2(sx sx + sy atan a ` 29.5 MPa txy saver 2 sx saver 180° 2 up2 up1 a 39.9906 MPa 90° 90° a 2 us2 a 90° + us1 42.47° us1 Point S1: saver up1 up2 ; 40.0 MPa s2 R us1 `b s1 R 40.0 MPa (b) MAXIMUM SHEAR STRESSES R (a) PRINCIPAL STRESSES up1 Point P1: s1 Point P2: s2 0 MPa saver)2 + txy2 txy 27 MPa 68.8° 21.2° tmax ; ; R 23.8° us2 0 MPa tmax 113.8° ; ; ; 40.0 MPa ; ; ...
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This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

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