619_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

619_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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Unformatted text preview: 07Ch07.qxd 9/27/08 1:20 PM Page 613 SECTION 7.5 Hooke’s Law for Plane Stress 613 Solution 7.5-10 Square plate in plane stress b 600 mm t 40 mm E 45 GPa v Px 480 kN sx Py 180 kN V 120 kN 14.4 * 106 mm3 ¢V eV0 2640 mm3 Px bt Py txy b 2t 0.35 (magnesium) sy V0 (Increase in volume) bt V bt 20.0 MPa STRAIN ENERGY 7.5 MPa Eq. (7-50): u 5.0 MPa G CHANGE IN VOLUME Eq. (7-47): e 90 k, Py 12 (sx + s2 y 2E E 2(1 + ) 2 sxsy) + t2 xy 2G 16.667 GPa Substitute numerical values: 1 2 6 183.33 * 10 u 4653 Pa U (sx + sy) E uV0 Problem 7.5-11 Solve the preceding problem for an aluminum plate with b Px ; 20 k, and V 67.0 N # m 12 in., t 67.0 J 1.0 in., E ; 10,600 ksi, 15 k. Solution 7.5-11 Square plate in plane stress b E t 12.0 in. 1.0 in. 10,600 ksi Px 0.33 (aluminum) Px bt Py sx 90 k STRAIN ENERGY Py 20 k sy V 15 k txy bt V bt Eq. (7-50): u 7500 psi G 1667 psi 1 2 E u V0 b 2t 144 in.3 ¢V eV0 0.0423 in.3 294 * 10 (Increase in volume) ; 6 uV0 373 in.-lb 2 sxsy) + 3985 ksi 2.591 psi U 1250 psi (sx + sy) E 2(1 + ) Substitute numerical values: CHANGE IN VOLUME Eq. (7-47): e 1 (s2 + s2 y 2E x ; t2 xy 2G 0.33, ...
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This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

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