657_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

657_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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Unformatted text preview: 08Ch08.qxd 9/18/08 11:03 AM Page 651 651 SECTION 8.2 Spherical Pressure Vessels Problem 8.2-4 A rubber ball (see figure) is inflated to a pressure of 60 kPa. At that pressure the diameter of the ball is 230 mm and the wall thickness is 1.2 mm. The rubber has modulus of elasticity E 3.5 MPa and Poisson’s ratio v 0.45. Determine the maximum stress and strain in the ball. Prob. 8.2-4, 8.2-5 Solution 8.2-4 Rubber ball CROSS-SECTION MAXIMUM STRESS (EQ. 8-1) smax pr 2t (60 kPa)(115 mm) 2(1.2 mm) ; 2.88 MPa MAXIMUM STRAIN (EQ. 8-4) Radius: r (230 mm)/2 Internal pressure: p t âmax 60 kPa Wall thickness: 115 mm pr (1 2tE (60 kPa)(115 mm) (0.55) 2(1.2 mm)(3.5 MPa) v) 1.2 mm ; 0.452 Modulus of elasticity: E 3.5 MPa (rubber) Poisson’s ratio: 0.45 (rubber) v Problem 8.2-5 Solve the preceding problem if the pressure is 9.0 psi, the diameter is 9.0 in., the wall thickness is 0.05 in., the modulus of elasticity is 500 psi, and Poisson’s ratio is 0.45. Solution 8.2-5 Rubber ball CROSS-SECTION Modulus of elasticity: E 500 psi (rubber) Poisson’s ratio: 0.45 (rubber) v MAXIMUM STRESS (EQ. 8-1) smax Radius: r 1 (9.0 in.) 2 Internal pressure: p 9.0 psi Wall thickness: t 0.05 in. 4.5 in. pr 2t (9.0 psi)(4.5 in.) 2(0.05 in.) 405 psi ; MAXIMUM STRAIN (EQ. 8-4) âmax pr (1 2tE 0.446 v) ; (9.0 psi)(4.5 in.) 2(0.05 in.)(500 psi) (0.55) ...
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This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

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