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660_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

# 660_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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654 CHAPTER 8 Applications of Plane Stress Problem 8.2-10 Solve the preceding problem if the diameter is 500 mm, the pressure is 18 MPa, the yield stress in tension is 975 MPa, the yield stress in shear is 460 MPa, the factor of safety is 2.5, the modulus of elasticity is 200 GPa, Poisson’s ratio is 0.28, and the normal strain must not exceed 1210 ± 10 ² 6 . Solution 8.2-10 r ³ 250 mm E ³ 200 GPa p ³ 18 MPa v ³ 0.28 (steel) s Y ³ 975 MPa n ³ 2.5 t Y ³ 460 MPa ´ max ³ 1210 ± 10 ² 6 M INIMUM WALL THICKNESS t (1) T ENSION ( EQ . 8-1) ³ (18 MPa)(250 mm) 2 975 MPa 2.5 ³ 5.769 mm t 1 ³ pr 2 s max ³ pr 2 a s Y n b s max ³ pr 2 t 1 (2) S HEAR ( EQ . 8-3) (3) S TRAIN ( EQ . 8-4) t 3 µ t 2 µ t 1 Thus, t min ³ 6.69 mm ; ³ 6.694 mm ³ (18 MPa)(250 mm) 2
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Unformatted text preview: 1 1210 * 10 ² 6 2 (200 GPa) 0.72 t 3 ³ pr 2 â max E (1 ² v ) â max ³ pr 2 t 3 E (1 ² v ) t 2 ³ pr 4 t Y n ³ (18 MPa)(250 mm) 4 460 MPa 2.5 ³ 6.114 mm t max ³ pr 4 t 2 Problem 8.2-11 A hollow pressurized sphere having radius r ³ 4.8 in. and wall thickness t ³ 0.4 in. is lowered into a lake (see figure). The compressed air in the tank is at a pressure of 24 psi (gage pressure when the tank is out of the water). At what depth D will the wall of the tank be subjected to a compressive stress of 90 psi? D 08Ch08.qxd 9/18/08 11:03 AM Page 654...
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