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Unformatted text preview: 08Ch08.qxd 9/18/08 11:03 AM Page 655 SECTION 8.3 Cylindrical Pressure Vessels 655 Solution 8.2-11 Pressurized sphere under water
t 4.8 in.
0.4 in. (1) IN AIR: p1 D0
g depth of water (in.) p2 gD0 24 psi
density of water 3 62.4 lb/ft 62.4 lb/ft3
1728 in.3/ ft3 b D0 0.036111 D0 ( psi) Compressive stress in tank wall equals 90 psi.
(Note: s is positive in tension.) 24 psi s pr
90 psi (1) IN AIR
(2) UNDER WATER: p1 a 24 psi p2)r ( p1 s 2t 90 psi 0.03611 D0)(4.8 in.) (24 psi 2(0.4 in.)
144 Solve for D0: D0 0.21667 D0
1080 in. (2) UNDER WATER Cylindrical Pressure Vessels
When solving the problems for Section 8.3, assume that the given radius or diameter is an
inside dimension and that all internal pressures are gage pressures. Problem 8.3-1 A scuba tank (see figure) is being designed for an internal pressure of
1600 psi with a factor of safety of 2.0 with respect to yielding. The yield stress of the steel is
35,000 psi in tension and 16,000 psi in shear.
If the diameter of the tank is 7.0 in., what is the minimum required wall thickness? 90 ft ; ...
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This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.
- Fall '11