661_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

661_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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Unformatted text preview: 08Ch08.qxd 9/18/08 11:03 AM Page 655 SECTION 8.3 Cylindrical Pressure Vessels 655 Solution 8.2-11 Pressurized sphere under water CROSS-SECTION r t 4.8 in. 0.4 in. (1) IN AIR: p1 D0 p1 g depth of water (in.) p2 gD0 24 psi density of water 3 62.4 lb/ft 62.4 lb/ft3 1728 in.3/ ft3 b D0 0.036111 D0 ( psi) Compressive stress in tank wall equals 90 psi. (Note: s is positive in tension.) 24 psi s pr 2t 90 psi (1) IN AIR (2) UNDER WATER: p1 a 24 psi p2)r ( p1 s 2t 90 psi 0.03611 D0)(4.8 in.) (24 psi 2(0.4 in.) 144 Solve for D0: D0 0.21667 D0 234 0.21667 1080 in. (2) UNDER WATER Cylindrical Pressure Vessels When solving the problems for Section 8.3, assume that the given radius or diameter is an inside dimension and that all internal pressures are gage pressures. Problem 8.3-1 A scuba tank (see figure) is being designed for an internal pressure of 1600 psi with a factor of safety of 2.0 with respect to yielding. The yield stress of the steel is 35,000 psi in tension and 16,000 psi in shear. If the diameter of the tank is 7.0 in., what is the minimum required wall thickness? 90 ft ; ...
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This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

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