662_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

662_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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Unformatted text preview: 08Ch08.qxd 9/18/08 656 11:03 AM Page 656 CHAPTER 8 Applications of Plane Stress Solution 8.3-1 Scuba tank sallow sY n 17,500 psi t allow tY n 8,000 psi Find required wall thickness t. (1) BASED ON TENSION (EQ. 8-5) t1 pr (1600 psi)(3.5 in.) sallow 17,500 psi Cylindrical pressure vessel p 1600 psi r 3.5 in. n sY 2.0 d 35,000 psi 7.0 in. Y pr 2tallow tmin and wall thickness t 0.350 in. 2(8,000 psi) t1 ; 0.350 in. Problem 8.3-2 A tall standpipe with an open top (see figure) has diameter d pr 2t (1600 psi)(3.5 in.) Shear governs since t2 16,000 psi 0.320 in. tmax (2) BASED ON SHEAR (EQ. 8-10) t2 pr t smax 2.2 m d 20 mm. (a) What height h of water will produce a circumferential stress of 12 MPa in the wall of the standpipe? (b) What is the axial stress in the wall of the tank due to the water pressure? h Solution 8.3-2 d 2.2 m r 1.1 m weight density of water g height of water p 20 mm 9.81 kN/m3 h water pressure t pr t 12 MPa 12 (20) 0.00981 (1.1) (b) AXIAL STRESS IN 22.2 m THE WALL DUE TO WATER PRESSURE ALONE h (a) HEIGHT OF WATER s1 h 0.00981h (1.1 m) 20 mm Because the top of the tank is open, the internal pressure of the water produces no axial (longitudinal) stresses in the wall of the tank. Axial stress equals zero. ; ...
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This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

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