695_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

695_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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Unformatted text preview: 08Ch08.qxd 9/18/08 11:06 AM Page 689 689 SECTION 8.5 Combined Loadings STRESS ELEMENT AT THE TOP OF THE BAR AT B sx 0 sy sB txy tB st A (2 + 24 + p2) MAXIMUM TENSILE STRESS 16qR2 s1 pd 3 29.15 qR2 ; d3 24 + p2) PRINCIPAL STRESSES: s1, 2 sx + sy sB ; a 2 A ; 2 32qR 2 pd 3 16qR 2 pd 3 A a sy sx 2 sc sB 2 2 b + tB 2 (2 ; 24 + p2 ) ; MAXIMUM COMPRESSIVE STRESS 2 2 b + txy a 32qR2 pd 3 2 b +a 16qR2 d3 b 16qR2 s2 pd 3 (2 8.78 2 qR2 ; d3 24 + p 2 MAXIMUM IN-PLANE SHEAR STRESS (EQ. 7-26) 1 (s 21 tmax s2) 16qR2 pd 3 ; z Problem 8.5-13 An arm ABC lying in a horizontal plane and supported at A (see figure) is made of two identical solid steel bars AB and BC welded together at a right angle. Each bar is 20 in. long. Knowing that the maximum tensile stress (principal stress) at the top of the bar at support A due solely to the weights of the bars is 932 psi, determine the diameter d of the bars. y A x B C Solution 8.5-13 Horizontal arm ABC L length of AB and BC d diameter of AB and BC A cross-sectional area pd2/4 g weight density of steel q weight per unit length of bars gA pgd2/4 (1) ...
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This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

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