810_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

810_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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Unformatted text preview: 10Ch10.qxd 804 9/27/08 7:29 AM Page 804 CHAPTER 10 Statically Indeterminate Beams B.C. B.C. B.C. 1 ¿ (0) 0 2 (0) ‹ C3 0 3 ¿ (L) B.C. 1 v 2L 4 q0 a b p ‹ C4 p4EI c q0 a L + C2L 2 4 (L) 2L 3 b p (6) 2L 4 q0 a b p (7) C2 q EIv –¿ p) q0 a x q0 L p4 EIv – p) p4 q0 a SHEAR FORCE (EQ. 2) 48(4 p) 2L px q0 sin a b + q0 L 4 p 2L p + C1 REACTIONS RA RB V(0) p) 48(4 4 p a V(L) ; q0 L b q0 L + C2 MB q0 a 2 4 p 2L b+ p 32(p 3L2 3) 4 p x3 6 (1) b + C1 (2) x4 12L2 x5 60L2 x4 24 b + C1x + C2 b (4) x3 b + C1 6 360L2 x2 + C3x + C4 2 (5) 16(6 q0 L2 p) p4 q0 L2 ; B.C. 1 ¿ (0) 0 ‹ C3 0 B.C. ; 48(4 p) 2L 4 px b cos a b + p 2L p4 16(6 p) x3 * q0 L 4 6 p q0 a 2 2 (0) 0 ‹ C4 0 3 ¿ (L) 0 ; ‹ C1L + 2C2 B.C. 4 v( L) 3 q L2 10 0 (6) 7 q L2 30 0 (7) 0 Solve Eqs. (6) and (7): C1 13 qL 30 0 C2 1 q L2 15 0 SHEAR FORCE (EQ. 2) 4 x 2L + q0 a b , or p 2 (3) x6 DEFLECTION CURVE (EQ. 5) * q0 L2 b L2 x2 2 ‹ C1L + 3C2 EIv x2 B.C. p) 48(4 2 p From equilibrium MA ; b x2 + C2 x + C3 2 q0 a EIv x3 q0 a M q0 L2 EIv ¿ V L2 q0 a 1 EIv –– Solve Eqs. (6) and (7): 16(6 x2 q0 a1 (b) Loading q p) q0 L x 3 DIFFERENTIAL EQUATION L L2 ‹ C1 + C2 6 2 48(4 px b + 8(4 2L p) q0 L2x 2 + 16 q0 L4 d 8(6 0 3 C1 16 q0 L4 cos a 0 2 ‹ C1 0 V q0 a x x3 2 3L b+ 13 qL 30 0 ...
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