834_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

834_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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Unformatted text preview: 10Ch10.qxd 9/27/08 828 7:36 AM Page 828 CHAPTER 10 Statically Indeterminate Beams LOWER BEAM 11qL 32 RA (M CD)max 11L 32 x1 M1 5qL2 64 ; NUMERICAL VALUES 2 M max 5qL2 64 FL 4 M max q 121qL 2048 3qL2 64 L (M AB)max 121qL2 2048 6.4 kN/m 4m (M AB)max 6.05 kN # m 8.0 kN # m (M CD)max S6 S 6 12.5 steel I-beam with E 30 106 psi. The simple beam DE is a wood beam 4 in. 12 in. (normal dimension) in cross section with E 1.5 106 psi. A steel rod AC of diameter 0.25 in., length 10 ft, and E 30 106 psi serves as a hanger joining the two beams. The hanger fits snugly between the beam before the uniform load is applied to beam DE. Determine the tensile force F in the hanger and the maximum bending moments MAB and MDE in the two beams due to the uniform load, which has intensity q 400 lb/ft . (Hint: To aid in obtaining the maximum bending moment in beam DE, draw the shear-force and bending-moment diagrams.) A 12.5 B 6 ft Steel rod E D C Wood beam 10 ft Solution 10.4-19 Beams joined by a hanger (2) HANGER AC tensile force in hanger Select F as redundant. (1) CANTILEVER BEAM AB 22.1 in.4 I1 L1 6 ft E1 30 * 106 psi (dA)1 72 in. FL 3 1 3E 1I1 187.66 * 10 6 F e F d Ib in. d E2 10 ft 400 lb/ft 10 ft S 6 * 12.5 ; ; Problem 10.4-19 The cantilever beam AB shown in the figure is an F ; L2 0.25 in. 6 30 * 10 psi 10 ft 120 in. ...
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