864_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

864_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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Problem 11.3-14 The hoisting arrangement for lifting a large pipe is shown in the figure. The spreader is a steel tubular section with outer diameter 70 mm and inner diameter 57 mm. Its length is 2.6 m and its modulus of elasticity is 200 GPa. Based upon a factor of safety of 2.25 with respect ot Euler buckling of the spreader, what is the maximum weight of pipe that can be lifted?(Assume pinned conditions at the ends of the spreader.) 858 CHAPTER 11 Columns Solution 11.3-14 A LLOWABLE L OAD P allow ± P cr n P allow ± 88.6 kN P cr ± p 2 EI L 2 P cr ± 199 kN I ± p 64 1 d 2 4 ² d 1 4 2 I ± 660.4 * 10 3 mm 4 n ± 2.25 a ± atan a 7 10 b d 1 ± 57 mm L ± 2.6 m E ± 30000 ksi d 2 ± 70 mm E QUILIBRIUM OF JOINT A S OLVE THE EQUATION
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Unformatted text preview: M AXIMUM WEIGHT OF PIPE ; W max ± 2 P allow tan( a ) W max ± 124 kN W ± 2 P tan( a ) © F vert ± T sin( a ) ² w 2 ± © F horiz ± ² P + T cos( a ) ± Solution 11.3-13 P cr ± p 2 EI L 2 P cr ± 70.40 k I ± p 64 1 d 2 4 ² d 1 4 2 I ± 1.132 in. 4 L ± 5.75 ft n ± 2.5 a ± 75° E ± 30000 ksi d 2 ± 2.5 in. d 1 ± 2.0 in. A LLOWABLE LOAD E QUILIBRIUM OF JOINT B Thus ; F allow ± P allow 2 cos ( a ) F allow ± 54.4 k P ± 2 F cos ( a ) P allow ± P cr n P allow ± 28.16 k F 10 10 7 7 A B Spreader Cable Cable Pipe 11Ch11.qxd 9/27/08 2:21 PM Page 858...
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This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

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