880_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

880_Mechanics SolutionInstructors_Sol.Manual-Mechanics_Materials_7e.book_Gere_light.1

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Unformatted text preview: 11Ch11.qxd 9/27/08 874 3:39 PM CHAPTER 11 Columns Problem 11.5-5 e Page 874 Solve the preceding problem for a column with 12 ft, I 21.7 in.4, and E 30 * 106 psi. 0.20 in., L Solution 11.5-5 Column with eccentric loads Column has pinned ends Use Eq. (11-54) for the deflection at the midpoint (maximum deflection): d e c sec a pP b 2 A Pcr 1d SOLVE EQ. (2) FOR P: P (1) 125.6 c arc cos a 2 0.2 bd 0.2 + d ; LOAD-DEFLECTION DIAGRAM DATA e E I 0.20 in. L 12 ft 30 * 106 psi 21.7 in.4 144 in. CRITICAL LOAD Pcr p2EI (0.20) [sec (0.08924 1P) L2 309.9 k MAXIMUM DEFLECTION (FROM EQ. 1) d Units: P kips d Angles are in radians. 1] (2) inches Problem 11.5-6 A wide-flange member (W 200 * 22.5) is compressed by axial loads that have a resultant P acting at the point shown in the figure. The member has modulus of elasticity E 2000 GPa and pinned conditions at the ends. Lateral supports prevent any bending about the weak axis of the cross section. If the length of the member is 6.2 mm, and the deflection is limited to 6.5 mm, what is the maximum allowable load Pallow? P W 200 Solution 11.5-6 W 200 * 22.5 d 6.5 mm e d 2 e E I 6 p2EI L2 103 mm Pcr 4 20 * 10 mm CRITICAL LOAD Pcr L 200 GPa 1027 kN 6.2 m d 206 mm Mamimum deflection d Solve for P Pallow e asec a P p b 2 A Pcr 49.9 kN ; 22.5 1b ...
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This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.

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