Unformatted text preview: 20 k Substitute into Eq. (1): (b) M AXIMUM PERMISSIBLE LENGTH Solve Eq. (1) for the length : (2) Substitute numerical values: L max ± 46.2 in. ; L ± 2 A EI P arccos c P ( ec / r 2 ) s max A ² P d L s allow ± 18,000 psi s max ± 17.3 ksi ; P e Problem 11.6-2 A brass bar ( ) with a square cross section is subjected to axial force having a resultant P acting at distance e from the center (see figure). The bar is pin supported at the ends and is 0.6 m in length. The side dimension b of the bar is 30 mm and the eccentricity e of the load is 10 mm. If the allowable stress in the brass is 150 MPa, what is the allowable axial force P allow ? E ± 100 GPa Solution 11.6-2 Bar with square cross section Pinned supports. D ATA e ± 10 mm E ± 100 GPa b ± 30 mm L ± 0.6 m s allow ± 150 MPa S ECANT FORMULA (E Q . 11-59): (1) s max ± P A c 1 + ec r 2 sec a L 2 r A P EA bd 11Ch11.qxd 9/27/08 3:39 PM Page 880...
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- Fall '11
- Compressive stress, square cross section, maximum permissible length