SECTION 11.6The Secant Formula883Problem 11.6-6A circular aluminum tube with pinned ends supports a load kN acting at distance from the center (see figure). The length of the tube is m and its modulus of elasticity is GPa.If the maximum permissible stress in the tube is 20 MPa,what is the required outer diameter if the ratio of diameter is to be d1/d2±0.9?d2733.5e±50 mmP±18Solution 11.6-6Aluminum tubePinned ends.DATAkN±20 MPa±0.9SECANT FORMULA(EQ. 11-59)()r±0.33634 d2(r±mm)r2±IA±0.11313d22(d2±mm; r2±mm2)d2±mm;I±mm4I±p64(d24²d14)±p64[d24²(0.9d2)4]±0.016881d24PA±18,000 N0.14923 d22±120,620d22aPA±MPabd2±mm;A±mm2A±p4(d22²d12)±p4[d22²(0.9d2)2]±0.14923d22smax±PAc1+ecr2secaL2rAPEAbdd1/d2smaxL±3.5 mE±73 GPae±50 mmP±18SUBSTITUTE THE ABOVE EXPRESSIONS INTOEQ. (1):(2)SOLVEEQ. (2) NUMERICALLY:d2±131 mm;³c1
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This note was uploaded on 12/22/2011 for the course MEEG 310 taught by Professor Staff during the Fall '11 term at University of Delaware.