HW Solutions Stat 25

HW Solutions Stat 25 - b. H0 : 3 = 0, Ha : 3 = 0. scfw_b3 =...

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b. H 0 : β 3 =0 , H a : β 3 6 =0 . s { b 3 } = . 97459, t =1 . 77739 /. 97459 = 1 . 8237, t ( . 95; 41) = 1 . 68288. If | t |≤ 1 . 68288 conclude H 0 , otherwise H a . Conclude H a . Alternatively, SSR ( X 1 X 2 | X 1 ,X 2 ) = 255 . 9, SSE ( X 1 ,X 2 ,X 1 X 2 ) = 3154 . 44, F = (255 . 9 / 1)
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This note was uploaded on 12/21/2011 for the course STA 2014 taught by Professor Davehatley during the Fall '11 term at UNF.

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