HW Solutions Stat 63

HW Solutions Stat 63 - d. H0 : all i equal zero (i = 1, 2,...

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d. H 0 : all α i equal zero ( i =1 , 2 , 3), H a : not all α i equal zero. F = 158 . 361 / 2 . 389=66 . 29, F ( . 95; 2 , 30)=3 . 32. If F 3 . 32 conclude H 0 , otherwise H a . Conclude H a . P -value = 0+ H 0 : β 1 = β 2 =0 , H a : not both β 1 and β 2 equal zero. F =5 . 444 / 2 . 389=2 . 28, F ( . 95; 1 , 30)=4 . 17. If F 4 . 17 conclude H 0 , otherwise H a . Conclude H 0 . P -value = . 14 e. α . 143 g. SSA = SSTR , SSB + SSAB + SSE = ,yes 19.14. a. ¯ Y 11 . =2 . 475, ¯ Y 12 . =4 . 600, ¯ Y 13 . . 575, ¯ Y 21 . . 450, ¯ Y 22 . =8 . 925, ¯ Y 23 . =9 . 125, ¯ Y 31 . . 975, ¯ Y 32 . =10 . 275, ¯ Y 33 . =13 . 250 b. e ijk : ij j j =3 1 . 075 0 . 225 . 225 . 400 . 075 . 175 . 300 . 175 . 025 . 100 . 025 j j 2 . 350 . 025 . 025 . 250 . 175 . 175 . 050 . 225 . 425 . 150 . 075 . 275 j j 3 . 125 . 375 . 250 . 275 . 225 . 250 . 075 . 325 . 050 . 225 . 175 . 050 d. r = . 988 19.15. b. Source SS df MS Treatments 373 . 1 0 584 6 . 638 A (ingredient 1) 220 . 020 2 110 . 010 B (ingredient 2) 123 . 6 6 026 1 . 830 AB interactions 29 . 425 4 7 . 356 Error 1 . 625 27 . 0602 Total 374 . 730 35 c. H 0 : all ( αβ ) ij equal zero, H a : not all ( αβ ) ij equal zero. F =7 . 356 /. 0602 = 122 . 19, F ( . 95; 4 , 27)=2 . 73. If F
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This note was uploaded on 12/21/2011 for the course STA 2014 taught by Professor Davehatley during the Fall '11 term at UNF.

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