HW Solutions Stat 64

# HW Solutions Stat 64 - e 19.20 a b.143 Y11 = 222.00 Y12 =...

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e. α . 143 19.20. a. ¯ Y 11 . = 222 . 00, ¯ Y 12 . = 106 . 50, ¯ Y 13 . =60 . 50, ¯ Y 21 . =62 . 25, ¯ Y 22 . =44 . 75, ¯ Y 23 . =38 . 75 b. e ijk : ij =1 j =2 j =3 11 83 . 5 4 . 5 16 11 . 5 . 5 5 3 . 57 . 5 3 11 . 5 2 . 5 j j 28 . 75 2 . 25 1 . 75 9 . 25 7 . 25 5 . 75 5 . 75 13 . 75 1 . 25 5 . 25 4 . 25 6 . 25 d. r = . 994 19.21. b. Source SS df MS Treatments 96 , 024 . 37500 5 19 , 204 . 87500 A (type) 39 , 447 . 04167 1 39 , 447 . 04167 B (years) 36 , 412 . 00000 2 18 , 206 . 00000 AB interactions 20 , 165 . 33333 2 10 , 082 . 66667 Error 1 , 550 . 25000 18 86 . 12500 Total 97 , 574 . 62500 23 c. H 0 : all ( αβ ) ij equal zero, H a : not all ( αβ ) ij equal zero. F =10 , 082 . 66667 / 86 . 12500 = 117 . 07, F ( . 99; 2 , 18)=6 . 01. If F 6 . 01 conclude H 0 , otherwise H a . Conclude H a . P -value = 0+ d. H 0 : α 1 = α 2 =0 , H a : not both α 1 and α 2 equal zero. F =39 , 447 . 04167 / 86 . 12500 = 458 . 02, F ( . 99; 1 , 18)=8 . 29. If F 8 . 29 conclude H 0 , otherwise H a . Conclude H a . P -value = 0+ H 0 : all β j equal zero ( j , 2 , 3), H a : not all β j equal zero. F =18 , 206 . 00000 / 86 . 12500 = 211 . 39, F ( . 99; 2 , . 01. If F 6 . 01 conclude H 0 , otherwise H a . Conclude H a . P -value = 0+ e. α . 030 19.27. a. B = t ( . 9975; 75) = 2 . 8925, q ( . 95; 5 , 75)=3 . 96, T . 800 b. B = t ( . 99167; 27) = 2 . 552, q ( . 95; 3 , 27)=3 . 51, T . 482 19.30. a. s { ¯ Y 11 . } = . 631, t ( . 975; 30) = 2 . 042, 21 . 66667 ± 2 . 042( . 631), 20
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## This note was uploaded on 12/21/2011 for the course STA 2014 taught by Professor Davehatley during the Fall '11 term at UNF.

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