HW Solutions Stat 68

HW Solutions Stat 68 - . 3391) 5 . 99 D 5 2 . 51 4 . 20 5 ....

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Chapter 20 TWO-FACTOR STUDIES – ONE CASE PER TREATMENT 20.2. b. Source SS df MS Location 37 . 0050 3 12 . 3350 Week 47 . 0450 1 47 . 0450 Error . 3450 3 . 1150 Total 84 . 3950 7 H 0 : all α i equal zero ( i =1 , ..., 4), H a : not all α i equal zero. F =12 . 3350 /. 1150 = 107 . 26, F ( . 95; 3 , 3 )=9 . 28. If F 9 . 28 conclude H 0 , otherwise H a . Conclude H a . P -value = . 0015 H 0 : β 1 = β 2 =0 , H a : not both β 1 and β 2 equal zero. F =47 . 0450 /. 1150 = 409 . 09, F ( . 95; 1 , 3 )=10 . 1. If F 10 . 1 conclude H 0 , otherwise H a . Conclude H a . P -value = . 0003. α . 0975 c. ˆ D 1 = ¯ Y 1 . ¯ Y 2 . =18 . 95 14 . 55=4 . 40, ˆ D 2 = ¯ Y 1 . ¯ Y 3 . =18 . 95 14 . 60=4 . 35, ˆ D 3 = ¯ Y 1 . ¯ Y 4 . =18 . 95 18 . 80 = . 15, ˆ D 4 = ¯ Y 2 . ¯ Y 3 . = . 05, ˆ D 5 = ¯ Y 2 . ¯ Y 4 . = 4 . 25, ˆ D 6 = ¯ Y 3 . ¯ Y 4 . = 4 . 20, ˆ D 7 = ¯ Y . 1 ¯ Y . 2 =14 . 30 19 . 15 = 4 . 85, s { ˆ D i } = . 3391 ( i =1 , ..., 6), s { ˆ D 7 } = . 2398, B = t ( . 99286; 3) = 5 . 139 4 . 40 ± 5 . 139( . 3391) 2 . 66 D 1 6 . 14 4 . 35 ± 5 . 139( . 3391) 2 . 61 D 2 6 . 09 . 15 ± 5 . 139( . 3391) 1 . 59 D 3 1 . 89 . 05 ± 5 . 139( . 3391) 1 . 79 D 4 1 . 69 4 . 25 ±
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Unformatted text preview: . 3391) 5 . 99 D 5 2 . 51 4 . 20 5 . 139( . 3391) 5 . 94 D 6 2 . 46 4 . 85 5 . 139( . 2398) 6 . 08 D 7 3 . 62 20.3. a. 32 = Y 3 . + Y . 2 Y .. = 14 . 600 + 19 . 150 16 . 725 = 17 . 025 b. s 2 { 32 } = . 071875 c. s { 32 } = . 2681, t ( . 975; 3) = 3 . 182, 17 . 025 3 . 182( . 2681) , 16 . 172 32 17 . 878 21.4. D = ( 4 . 13473) / (18 . 5025)(11 . 76125) = . 019, SSAB = . 0786 , SSRem = . 2664. 20-1...
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This note was uploaded on 12/21/2011 for the course STA 2014 taught by Professor Davehatley during the Fall '11 term at UNF.

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