HW Solutions Stat 85

# HW Solutions Stat 85 - H0 all)ik equal zero Ha not all)ik...

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H 0 : all ( αγ ) ik equal zero, H a : not all ( αγ ) ik equal zero. F = . 20167 / 3 . 35875 = . 06, F ( . 975; 1 , 16)=6 . 12. If F 6 . 12 conclude H 0 , otherwise H a . Conclude H 0 . P -value = . 81 H 0 : all ( βγ ) jk equal zero, H a : not all ( βγ ) jk equal zero. F =2 . 94000 / 3 . 35875 = . 875, F ( . 975; 1 , 16 )=6 . 12. If F 6 . 12 conclude H 0 , otherwise H a . Conclude H 0 . P -value = . 36 e. H 0 : all α i equal zero ( i =1 , 2), H a : not all α i equal zero. F = 788 . 90667 / 3 . 35875 = 234 . 88, F ( . 975; 1 , 16)=6 . 12. If F 6 . 12 conclude H 0 , otherwise H a . Conclude H a . P -value = 0+ H 0 : all β j equal zero ( j =1 , 2), H a : not all β j equal zero. F =1 , 539 . 20167 / 3 . 35875 = 458 . 27, F ( . 975; 1 , 16)=6 . 12. If F 6 . 12 conclude H 0 , otherwise H a . Conclude H a . P -value = 0+ H 0 : all γ k equal zero ( k =1 , 2), H a : not all γ k equal zero. F =2 , 440 . 1667 / 3 . 35875 = 726 . 51, F ( .
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## This note was uploaded on 12/21/2011 for the course STA 2014 taught by Professor Davehatley during the Fall '11 term at UNF.

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