HW Solutions Stat 90

HW Solutions Stat 90 - F = 132.83750/4.36607 = 30.425, F...

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F = 132 . 83750 / 4 . 36607 = 30 . 425, F ( . 95; 4 , 28)=2 . 71. If F 2 . 71 conclude H 0 , otherwise H a . Conclude H a . P -value = 0+ c. ¯ Y . 1 =2 0 . 500, ¯ Y . 2 =2 3 . 625, ¯ Y . 3 =1 9 . 000, ¯ Y . 4 =2 9 . 375, ¯ Y . 5 =21 . 125, ˆ L 1 = ¯ Y . 1 ¯ Y . 2 = 3 . 125, ˆ L 2 = ¯ Y . 1 ¯ Y . 3 =1 . 500, ˆ L 3 = ¯ Y . 1 ¯ Y . 4 = 8 . 875, ˆ L 4 = ¯ Y . 1 ¯ Y . 5 = . 625, s { ˆ L i } =1 . 0448 ( i =1 , ..., 4), B = t ( . 9875; 28) = 2 . 369 3 . 125 ± 2 . 369(1 . 0448) 5 . 60 L 1 ≤− . 65 1 . 500 ± 2 . 369(1 . 0448) . 98 L 2 3 . 98 8 . 875 ± 2 . 369(1 . 0448) 11 . 35 L 3 ≤− 6 . 40 . 625 ± 2 . 369(1 . 0448) 3 . 10 L 4 1 . 85 d. ˆ L = 1 3 ( ¯ Y . 1 + ¯ Y . 3 + ¯ Y . 5 ) 1 2 ( ¯ Y . 2 + ¯ Y . 4 )= 6 . 29167, s { ˆ L } = . 6744 ,t ( . 975; 28) = 2 . 048, 6 . 29167 ± 2 . 048( . 6744), 7 . 67 L ≤− 4 . 91 25.23. a. H 0 :
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This note was uploaded on 12/21/2011 for the course STA 2014 taught by Professor Davehatley during the Fall '11 term at UNF.

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