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Ordinary Diff Eq Exam Review Solutions 5

# Ordinary Diff Eq Exam Review Solutions 5 - 1 Solutions 7 22...

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Unformatted text preview: 1 Solutions 7 22. 23. 24. We ﬁrst calculate Observe that deﬁned are so is not deﬁned at and . so the two intervals where is 25. The denominator of is deﬁned are is when and . . Thus the two intervals where 26. This is a diﬀerential equation we can solve by simple integration: We get . . 27. Integration gives 28. Integration (by parts) gives 29. Observe that . . Integration gives 30. We integrate two times. First, . . . Second, 31. We integrate two times. First, . 32. From Problem 19 the general solution is . It follows that . Second, . At and we get . ...
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