Ordinary Diff Eq Exam Review Solutions 14

Ordinary Diff Eq Exam Review Solutions 14 - 16 1 Solutions...

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Unformatted text preview: 16 1 Solutions , with as calculated. The temperature requested is . 36. The ambient temperature is . Equation (12) gives for the temperature at time . Since the initial temperature of the thermometer is we get . Thus . The constant is determined from the temperature at a second time: so . Thus , with . To answer the first question we solve the equation for . We get minutes. The temperature at is . 37. The ambient temperature is . Equation (12) gives for the temperature of the soda at time . Since the initial temperature of the soda is we get . Thus . The constant is determined from the temperature at a second time: . Thus , with . so The temperature at is . 38. The ambient temperature is . Equation (12) gives for the temperature of the coffee at time . We are asked to determine the initial temperature of the coffee so is unknown. However, we have the equations or Dividing the second equation by the first gives From the first equation we get so . . We now calculate 39. The ambient temperature is . Equation (12) gives for the temperature of the beer at time . Since the initial temperature of the beer is we get . Thus . The constant is determined from the temperature at a second time: so . Thus , with . We now solve the equation for and get . She should therefore put the beer in the refrigerator at p.m. 40. Let us start time model gives at 1980. Then . At . The Malthusian growth (1990) we have ...
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This note was uploaded on 12/22/2011 for the course MAP 2302 taught by Professor Bell,d during the Fall '08 term at UNF.

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