Unformatted text preview: 42 1 Solutions for
for
On the other hand,
for
for
It follows that is a solution. It is trivial to see that is a solution. There is no contraction to Theorem 5 since, in standard form
has a discontinuous
not even apply. Section 2.1
1. 2. near . So Picard’s theorem does ...
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 Fall '08
 BELL,D
 Standard form

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