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Unformatted text preview: 42 1 Solutions for
for
On the other hand,
for
for
It follows that is a solution. It is trivial to see that is a solution. There is no contraction to Theorem 5 since, in standard form
has a discontinuous
not even apply. Section 2.1
1. 2. near . So Picard’s theorem does ...
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This note was uploaded on 12/22/2011 for the course MAP 2302 taught by Professor Bell,d during the Fall '08 term at UNF.
 Fall '08
 BELL,D

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