Ordinary Diff Eq Exam Review Solutions 52

Ordinary Diff Eq Exam Review Solutions 52 - 54 1 Solutions...

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Unformatted text preview: 54 1 Solutions where and Thus , so use Theorem 1 to compute the 25. -chain: where and Continuing gives where and Thus tinue with Theorem 1 or replace Now either conwith of the last fraction to finish the calculation and get 26. Use Theorem 1 to compute the -chain: in the numerator ...
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This note was uploaded on 12/22/2011 for the course MAP 2302 taught by Professor Bell,d during the Fall '08 term at UNF.

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