Unformatted text preview: 56 1 Solutions where
and Continuing gives where
and
Thus . Now continue using Theorem 1 or replace by in the numerator of the last fraction to get
29. Use Theorem 1 to compute the chain: where
and For the second step in the chain: ...
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This note was uploaded on 12/22/2011 for the course MAP 2302 taught by Professor Bell,d during the Fall '08 term at UNF.
 Fall '08
 BELL,D

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