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Ordinary Diff Eq Exam Review Solutions 55

Ordinary Diff Eq Exam Review Solutions 55 - 1 Solutions 57...

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Unformatted text preview: 1 Solutions 57 where and Continuing gives where and Thus . The last fraction has a denominator with distinct linear factors so we get 30. Use Theorem 1 to compute the -chain: where and Continuing gives where and ...
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