Ordinary Diff Eq Exam Review Solutions 56

Ordinary Diff Eq Exam Review Solutions 56 - 58 1 Solutions...

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Unformatted text preview: 58 1 Solutions . The last fraction has Thus a denominator with distinct linear factors so we get 31. Use Theorem 1 to compute the -chain: where and Continuing gives where and Thus . Now continue using Theorem 1 or replace by in the numerator of the last fraction to get 32. Use Theorem 1 to compute the where and -chain: ...
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