Ordinary Diff Eq Exam Review Solutions 71

Ordinary Diff Eq Exam Review Solutions 71 - 1 Solutions 73...

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Unformatted text preview: 1 Solutions 73 Thus we get Replacing by in the above expression, gives the following expression : for the partial fraction decomposition of Section 2.4 1. 2. 3. 4. 5. 6. 7. First, we have . Partial fractions gives . So 8. Partial fractions gives . Thus ...
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