Ordinary Diff Eq Exam Review Solutions 95

Ordinary Diff Eq Exam Review Solutions 95 - 1 Solutions 23....

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Unformatted text preview: 1 Solutions 23. yes, 97 . 24. Parts (1) and (2) are done by computing where , , or . Then by Theorem 3, every function of the form is a solution to , where and are constants. If we want a solution to with and , then we need to solve for and : These equations give the answers for Part (3). , . Particular choices of and give (3)a. (3)b. (3)c. (3)d. 25.3)a. ( (3)b. (3)c. (3)d. 26.3)a. ( (3)b. (3)c. (3)d. 27. Write the equation in the standard form: Then , , and . These three functions are all continuous on the intervals and . Thus, Theorem 6 shows that if then the unique solution is also defined on the interval , and if , then the unique solution is defined on . 28. Maximal intervals are 29. where , , ...
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This note was uploaded on 12/22/2011 for the course MAP 2302 taught by Professor Bell,d during the Fall '08 term at UNF.

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