1 Solutions
115
1
2
3
1
1
2
3
4
5
6
7
t
y
3.
This function is
g
(
t
1)
h
(
t
1)
where
g
(
t
) =
t
, so the graph of
f
(
t
)
is
the graph of
g
(
t
) =
t
translated 1 unit to the right and then truncated at
t
= 1
, with the graph before
t
= 1
replaced by the line
y
= 0
. Thus the
graph is
0
1
2
0
1
2
3
t
y
4.
This function is
g
(
t
2)
h
(
t
2)
where
g
(
t
) =
t
2
, so the graph of
f
(
t
)
is
the graph of
g
(
t
) =
t
2
translated 1 unit to the right and then truncated
at
t
= 2
, with the graph before
t
= 2
replaced by the line
y
= 0
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 Fall '08
 BELL,D

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