Ordinary Diff Eq Exam Review Solutions 123

Ordinary Diff Eq Exam Review Solutions 123 - 3 7 7 5 13. 2...

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1 Solutions 125 4. RREF 5. t 2 ; 1 ( ± 2)( A ) = ± 1 0 ± 5 ± 2 ± 1 0 1 3 1 1 ² 6. m 2 (1 = 2)( A ) = 2 4 0 1 0 3 0 0 1 3 0 0 0 0 3 5 7. RREF 8. t 1 ; 3 ( ± 3)( A ) = 2 4 1 0 1 0 3 0 1 3 4 1 0 0 0 0 0 3 5 9. 2 4 1 0 0 2 0 1 0 1 0 0 1 ± 1 3 5 10. 2 4 1 0 0 ± 11 ± 8 0 1 0 ± 4 ± 2 0 0 1 9 6 3 5 11. 2 6 6 4 0 1 0 7 2 1 4 0 0 1 3 1 2 0 0 0 0 0 0 0 0 0 0 3 7 7 5 12. 2 6 6 4 1 2 0 0 3 0 0 1 0 2 0 0 0 1 0 0 0 0 0 0
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Unformatted text preview: 3 7 7 5 13. 2 4 1 0 0 1 1 1 0 1 0 ± 1 3 1 0 0 1 2 1 1 3 5 14. 2 6 6 6 6 4 1 0 2 0 1 1 0 0 0 0 0 0 0 0 0 3 7 7 7 7 5 15. 2 6 6 4 1 0 1 0 0 1 3 0 0 0 0 1 0 0 0 0 3 7 7 5...
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This note was uploaded on 12/22/2011 for the course MAP 2302 taught by Professor Bell,d during the Fall '08 term at UNF.

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