problem02_39 solution

University Physics with Modern Physics with Mastering Physics (11th Edition)

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2.39: a) From Eq. (2.13), with 0 = y v and g a y - = , , s m 94 . 2 m) 440 . 0 )( s m 80 . 9 ( 2 ) ( 2 2 0 0 = = - = y y g v y which is probably too precise for the speed of a flea; rounding down, the speed is about s m 9 . 2 . b) The time the flea is rising is the above speed divided by
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Unformatted text preview: g , and the total time is twice this; symbolically, s, 599 . ) m/s (9.80 ) m 440 . ( 2 2 ) ( 2 2 ) ( 2 2 2 = =-=-= g y y g y y g t or about 0.60 s....
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This document was uploaded on 02/04/2008.

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